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QCE Chemistry — Unit 3

Equilibrium Constant — Flashcards & Quiz

The equilibrium constant Kc quantifies the ratio of product to reactant concentrations at equilibrium, and QCE Chemistry Unit 3 tests both its calculation and its interpretation. You need to write Kc expressions correctly (excluding solids and pure liquids), relate magnitude to reaction favourability, and explain why Kc changes only with temperature. Combine this with Le Chatelier reasoning for most exam applications.

Sample Flashcards

Q1: Write the general expression for the equilibrium constant Kc.

For aA + bB ⇌ cC + dD: Kc = [C]^c[D]^d / [A]^a[B]^b. Concentrations are in mol L⁻¹ at equilibrium. Pure solids and pure liquids are excluded from the expression. A large Kc (≫1) means products are favoured; a small Kc (≪1) means reactants are favoured.

Q2: How does the value of Kc relate to the position of equilibrium?

Kc ≫ 1: equilibrium lies far to the right (products favoured). Kc ≈ 1: significant amounts of both reactants and products present. Kc ≪ 1: equilibrium lies far to the left (reactants favoured). Kc is constant at a given temperature — it changes ONLY when temperature changes, not with concentration or pressure changes.

Q3: What is Kp and how does it differ from Kc?

Kp is the equilibrium constant expressed in terms of partial pressures of gaseous species: Kp = (pC)^c(pD)^d / (pA)^a(pB)^b. Units depend on the reaction. Kp is related to Kc by Kp = Kc(RT)^Δn where Δn = moles of gaseous products − moles of gaseous reactants. If Δn = 0, Kp = Kc.

Q4: How does the equilibrium constant change when a reaction equation is reversed or multiplied?

Reversed: K_reverse = 1/K_forward. Multiplied by factor n: K_new = (K_original)ⁿ. Halved: K_new = √K_original. These relationships apply to both Kc and Kp. When combining equations (Hess's law style), multiply the K values.

Sample Quiz Questions

Q1: The value of Kc changes when the concentration of a reactant is increased.

Answer: FALSE

Kc is constant at a given temperature. Changing concentration shifts the position of equilibrium but does NOT change the value of Kc. Only temperature changes Kc.

Q2: A large Kc value indicates that products are favoured at equilibrium.

Answer: TRUE

When Kc ≫ 1, the numerator (products) is much larger than the denominator (reactants), meaning the equilibrium position favours product formation.

Q3: Pure solids and liquids are included in the Kc expression.

Answer: FALSE

Pure solids and pure liquids have constant concentrations and are excluded from Kc expressions. Only aqueous and gaseous species are included.

Related Concepts

Acid-Base Equilibria
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Last updated: March 2026 · 4 flashcards · 4 quiz questions