HSC Physics · Year 11
HSC Physics Module 1: Kinematics — Flashcards & Quiz
HSC Physics Module 1 Kinematics is the Year 11 module that describes and analyses motion without considering the forces and masses involved. These 20 free flashcards and 20 true/false quiz questions cover scalar and vector quantities, distance and displacement, speed and velocity, average and instantaneous velocity, acceleration, the equations of uniformly accelerated motion (v = u + at, s = ut + ½at², v² = u² + 2as), displacement–time and velocity–time graphs (gradients and areas), practical methods for measuring motion, relative velocity along a line, resolving and adding vectors in two dimensions, displacement and change in velocity on a plane, and relative motion in two dimensions such as a boat on a flowing river and an aeroplane in a crosswind. Aligned to the NESA Physics Stage 6 Syllabus (2017), Module 1: Motion in a Straight Line and Motion on a Plane.
Inside the Revizi HSC Physics deck
Across the whole subject there are 2,074 flashcards spanning 37 topics, including 383 formula cards.
Describes how the cards in this deck are pitched — not a measure of how hard the subject is.
Key Terms
- Displacement
- The change in position of an object: the straight-line distance from the initial to the final position together with its direction, making it a vector quantity. It differs from distance, which is the total path length travelled.
- Instantaneous velocity
- The velocity of an object at a specific instant, found as the gradient of the tangent to the displacement–time graph at that point. It contrasts with average velocity, which is total displacement divided by total time.
- Uniform acceleration
- Motion in which velocity changes by equal amounts in equal time intervals, giving a straight line on a velocity–time graph. The equations of motion (v = u + at, s = ut + ½at², v² = u² + 2as) apply only to this case.
- Relative velocity
- The velocity of one object as observed from the reference frame of another, found by vector subtraction: v(A, B) = v(A) − v(B). In two dimensions it is found with a vector diagram or components.
- Vector resolution
- Breaking a vector into two perpendicular components, usually horizontal and vertical: Vx = V cosθ and Vy = V sinθ, where θ is measured from the horizontal. It lets a two-dimensional problem be treated as two one-dimensional problems.
- Resultant vector
- The single vector that has the same effect as two or more vectors combined. For perpendicular components it has magnitude √(Vx² + Vy²) and direction tan⁻¹(Vy/Vx).
Sample Flashcards
Q1: What is the difference between a scalar and a vector quantity?
A scalar has magnitude only (e.g. speed, distance, mass, energy, time). A vector has both magnitude and direction (e.g. velocity, displacement, acceleration, force). Vectors are represented by arrows whose length indicates magnitude and orientation indicates direction.
Q2: What is displacement and how does it differ from distance?
Displacement is the straight-line distance from start to finish in a specified direction (vector). Distance is the total path length travelled (scalar). Displacement can be zero even when distance is large (e.g. a round trip).
Q3: Define average velocity and instantaneous velocity.
Average velocity = total displacement / total time (v_avg = Δs/Δt). Instantaneous velocity is the velocity at a specific moment — found from the gradient of a displacement-time graph at that point. Both are vectors.
Q4: Define acceleration and state its formula.
Acceleration is the rate of change of velocity: a = Δv/Δt = (v - u)/t. It is a vector quantity measured in m/s². Positive acceleration means speeding up in the direction of motion; negative acceleration (deceleration) means slowing down.
Q5: State the four equations of uniform acceleration (SUVAT).
v = u + at; s = ut + ½at²; v² = u² + 2as; s = ½(u + v)t. Where s = displacement, u = initial velocity, v = final velocity, a = acceleration, t = time. These apply ONLY when acceleration is constant.
Q6: What is free fall and what acceleration does an object experience?
Free fall is motion under gravity alone with no air resistance. Near Earth's surface, all objects experience a = g = 9.8 m/s² downward, regardless of mass. This was demonstrated by Galileo and confirmed on the Moon (feather and hammer experiment).
Q7: How do you analyse a boat crossing a flowing river relative to the bank?
The velocity of the boat relative to the bank is the vector sum of the boat’s velocity relative to the water and the water’s velocity relative to the bank: v(boat, bank) = v(boat, water) + v(water, bank). If the boat heads straight across, the current carries it downstream; to land directly opposite, it must head partly upstream so the upstream component cancels the current.
Q8: How do you find an aeroplane’s velocity relative to the ground in a crosswind?
Add the aeroplane’s velocity relative to the air (its heading and airspeed) to the wind’s velocity relative to the ground: v(plane, ground) = v(plane, air) + v(air, ground). The result gives the ground speed and the actual direction of travel (the track), which differs from the heading whenever the wind has a sideways component.
Sample Quiz Questions
Q1: Speed is a vector quantity because it describes how fast an object is moving.
Answer: FALSE
Speed is a SCALAR — it has magnitude only (how fast). Velocity is the vector equivalent, having both magnitude and direction. Speed = |velocity|.
Q2: Displacement can be zero even when the total distance travelled is large.
Answer: TRUE
If you return to your starting point, displacement = 0 regardless of distance. Example: running a complete lap of a 400 m track gives distance = 400 m but displacement = 0 m.
Q3: An object moving at constant speed must also be moving at constant velocity.
Answer: FALSE
Constant speed does not mean constant velocity. An object moving in a circle at constant speed has changing velocity because its direction is continuously changing. Velocity is a vector.
Q4: An object with zero velocity must have zero acceleration.
Answer: FALSE
An object at the peak of its trajectory has v = 0 but a = 9.8 m/s² (gravity still acts). A car at rest about to move has v = 0 but non-zero acceleration.
Q5: The SUVAT equations can only be used when acceleration is constant.
Answer: TRUE
The equations v = u + at, s = ut + ½at², v² = u² + 2as, s = ½(u+v)t are derived assuming constant (uniform) acceleration. For varying acceleration, calculus-based methods are needed.
Why It Matters
Kinematics sets up the language and tools used throughout Physics: describing motion precisely with displacement, velocity and acceleration, extracting information from the gradients and areas of motion graphs, and handling quantities as vectors. Motion on a Plane extends this to two dimensions, where vectors must be resolved into components and added — the same technique used for projectile motion in Module 5 and for charged-particle motion in fields in Module 6. Relative motion problems, such as a boat crossing a river or a plane in a crosswind, train you to state clearly what each velocity is measured relative to. Building fluency now with the equations of motion and with vector diagrams makes the Year 12 mechanics and electromagnetism modules much easier to tackle.
Key Concepts
Scalars, Vectors and Motion Graphs
Distinguish scalar quantities (distance, speed, time) from vector quantities (displacement, velocity, acceleration). On a displacement–time graph the gradient gives velocity; on a velocity–time graph the gradient gives acceleration and the area gives displacement. Average velocity is the gradient of a secant line; instantaneous velocity is the gradient of a tangent.
Equations of Uniformly Accelerated Motion
v = u + at, s = ut + ½at² and v² = u² + 2as relate displacement, initial and final velocity, acceleration and time when acceleration is constant. List the known quantities, identify the missing one, and choose the equation that does not contain it. Define a positive direction before substituting.
Vectors on a Plane
A vector can be resolved into perpendicular components (V cosθ and V sinθ), and perpendicular components can be added with Pythagoras and tan⁻¹ to give a single resultant. Displacement over several legs and change in velocity (Δv = v − u) on a plane are found by vector addition and subtraction, not by adding magnitudes.
Relative Motion
The velocity of A relative to B is v(A, B) = v(A) − v(B). Along a line this is simple subtraction with signs; in two dimensions it needs vector diagrams. Typical situations include two moving cars, a boat on a flowing river relative to the bank, and an aeroplane in a crosswind relative to the ground.
Common Mistakes to Avoid
- Confusing distance (scalar) with displacement (vector) — a displacement answer needs a direction, and displacement can be zero even when distance travelled is large.
- Applying the equations of uniformly accelerated motion when acceleration is not constant — for varying acceleration, use graphical methods such as the area under a velocity–time graph.
- Forgetting to define a positive direction at the start of a problem, then mixing signs for velocity, displacement and acceleration partway through the working.
- Adding the magnitudes of vectors that point in different directions (for example 200 km/h + 50 km/h for a plane in a crosswind) instead of using a vector diagram, Pythagoras or components.
- Reading velocity from a displacement–time graph by taking the y-axis value instead of calculating the gradient — velocity is the gradient (slope) of the displacement–time curve.
Study Tips
- Solve at least five motion-graph interpretation problems per study session — practise extracting velocity from displacement-time gradients and displacement from velocity-time areas.
- For SUVAT problems, always list known and unknown variables first, then select the equation that connects them — this systematic approach prevents errors under pressure.
- Draw a labelled vector diagram for every two-dimensional problem — head-to-tail for addition, and state what each velocity is measured relative to.
- Define your positive direction at the start of every problem and stick with it — inconsistent signs are a frequent source of errors in kinematics.
- Use spaced-repetition flashcards to drill SUVAT equations, unit conversions and graph-reading rules — building automaticity with fundamentals frees up working memory for complex problems.
- Before your exam, work through the practice questions in this set at least twice using spaced repetition. Testing yourself repeatedly is the most effective revision strategy for long-term retention.
Key Concepts to Master
Related Topics
Exam Prep & Study Notes
Frequently Asked Questions
What does HSC Physics Module 1 cover?
Module 1 covers Motion in a Straight Line (scalar and vector quantities, displacement, velocity, acceleration, average and instantaneous velocity, relative velocity along a line, motion graphs and the equations of uniformly accelerated motion) and Motion on a Plane (resolving and adding vectors, displacement and velocity changes in two dimensions, and relative motion of objects such as boats in currents and aircraft in crosswinds).
How many flashcards are in this set?
This free set contains 20 flashcards and 20 true/false quiz questions covering Module 1 Kinematics, aligned to the NESA Physics Stage 6 syllabus.
Is Module 1 Kinematics in the HSC exam?
Module 1 is a Year 11 module and is assessed through Year 11 school-based assessment. The HSC Physics examination is based on the Year 12 modules (5–8), but the vector and equations-of-motion skills from Module 1 are used again in Module 5, for example in projectile motion.
Last updated: 9 October 2026 · 20 sample flashcards · 20 sample quiz questions · Content aligned to the NESA Syllabus